思路：依次循环数组，如果次数为0，findid赋值为当前循环的值，如果次数为1，判断findid的值是否与当前循环的值相同，相同次数加1，否则减1，循环完留下的findid为“水王”。

package com.pre.one;//20173522 李秦public class Damot {    public static void main(String[] args)    {        String []ids= { "aa","bb","aa","aa","cc","aa" ,"aa","ee","aa","hh","jj"};        System.out.println(find(ids));    }    public static String find(String [] id)    {        if(id == null)        {            System.out.println("请输入id列表");            return null;        }        int n=id.length;        String findid=null;        int cishu,i;        for(i=cishu=0;i